can anyone solve: x^2 - 2^x =0 by algebraic method???
(x squared minus two to the power x equals zero)
of course, without using graphing calculator.

x = 2 satisfies the equation ......

isnt that a basic alzebra ,

x = 2 and 4

Take a logarithm of the equation, then segregate the x terms and the constants. Then take the derivative and solve the resulting equation for x.

HTH

hunk ji kasari ho ??

x^2 = 2^ x
2logx = xlog2
2logx = 0.301x
2(d/dx)logx = 0.301 (d/dx) x
1/x = 0.1505
x= 6.64
milena ni ta , kasari ho yeso gardine dukha garne ho ki

x = 0 and 2

x^2-2x = 0
x^2-2x+1=1
(x-1)^2=1
X=2

hina haina, nepali chori, you found the defivative, i.e the maxima of the curve. it is a smooth curve which is easy to show as it has derivtives for all values of x. but 2, and 4 arents the only points.

* bro , teslai bhanchha "fluke" , process is wrong, answer is luckily right . MCQ bhaidiyeko bhaye ta thyakkai mileko ni yaar

for this particular curve the minima is the solution.......

.

sujanks ko herda ta malai aaile 4 class ko yad aayo ni
maile tyo ta char class ma nai gareko hai¨¨

hum............

Sujan, thats Brilliant. ehe!!! Verify garnu paryo... :D

Panpate,
You learned that in 4th grade?
I think I did it in 11th. However, there is a mistake in that solution, I hope sujanks will finally let others know about it, or someone else can find it.

4 hoina mitra.. 6 class ma hola..., first time algebra.. class 6 ma padauthyo kyara.. unless you went to school that started algebra in class 4

My informations stand as before.
Tyo 4 mai ho
tara ke garne aaile dimag budo bhayechha mistake nai patta lagauna sakina yar....

Lau kasle kahile padheko thaha chhaina tara let me explain where it is wrong :

when you take the roots { Sq. Rt( 4-(9/2))^2} , there are + and - values on both side . after that its not you who take either positive or negatinve on both side . You take the sign on one side and its mathematics that guides what sign you have to take on other side.

Well any way this did remind me of my school days and do keep on throwing these memories of past.

yupe, the solution violates the law of indices. the square root of any positive number results in a positive and negative number of same value. so, the square root of 4 is not necessarily equal to 2, it could be -2.
.
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Is that the question look like? then I solved it! :)

x^2-2x = 0
x^2-2x+1=1
(x-1)^2=1
x-1 = 1 OR x-1 = -1

therefore x =0 or x =2

yesari kina mildaina??? bujhena ali!!! dimag ali slow bhayo..mafi pau

aye sorry..question nai galat padhechu!! oops